2024 New 1z1-829 Dumps - Real Oracle Exam Questions
Dependable 1z1-829 Exam Dumps to Become Oracle Certified
NEW QUESTION # 15
Given:
What is the result?
- A. Bicycle-1, car=3, motorcycle=1, truck=2)
- B. (Bicycle, car, motorcycle, truck)
- C. Compilation fails.
- D. (3:bicycle, 0:car, 0motercycle, 5:truck)
- E. Bicycle =7, car=7, motorcycle=7, truck=7)
Answer: C
Explanation:
Explanation
The answer is E because the code fragment contains several syntax errors that prevent it from compiling.
Some of the errors are:
The enum declaration is missing a semicolon after the list of constants.
The enum constants are not capitalized, which violates the Java naming convention for enums.
The switch expression is missing parentheses around the variable name.
The case labels are missing colons after the enum constants.
The default label is missing a break statement, which causes a fall-through to the next case.
The println statement is missing a closing parenthesis and a semicolon.
A possible corrected version of the code fragment is:
enum Vehicle { BICYCLE, CAR, MOTORCYCLE, TRUCK; } public class Test { public static void main(String[] args) { Vehicle v = Vehicle.BICYCLE; switch (v) { case BICYCLE: System.out.print("1"); break; case CAR: System.out.print("3"); break; case MOTORCYCLE: System.out.print("1"); break; case TRUCK: System.out.print("2"); break; default: System.out.print("0"); break; } System.out.println(); } } This would print 1 as the output. References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Enum Types
The switch Statement
NEW QUESTION # 16
Given:
Which action enables the code to compile?
- A. Replace 15 with item.display (''Flower'');
- B. Replace 3 with private static void display () {
- C. Replace 7 with public void display (string design) {
- D. Replace 2 with static string name;
Answer: C
Explanation:
Explanation
The answer is C because the code fragment contains a syntax error in line 7, where the method display is declared without any parameter type. This causes a compilation error, as Java requires the parameter type to be specified for each method parameter. To fix this error, the parameter type should be added before the parameter name, such as string design. This will enable the code to compile and run without any errors.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Java Methods
NEW QUESTION # 17
Given the code fragment:
What is the result?
- A. Dog
Dog - B. Cat
Dog - C. A NullPointerException is thrown
Cat
Cat - D. Cat
null
Answer: D
Explanation:
The answer is E because the code fragment creates a new Pet object with the name "Dog" and assigns it to the variable p. Then, it assigns p to p1. Next, it changes the name of p1 to "Cat". Then, it assigns p1 to p. Finally, it sets p to null and prints the name of p and p1. The output will be "Cat" and "null" because p is set to null and p1 still points to the Pet object with the name "Cat".
NEW QUESTION # 18
Given:
Which statement is true?
- A. The program throws outofStockException.
- B. The program fails to compile.
- C. The program throws ClassCastException
- D. The program throws StockException.
Answer: B
Explanation:
Explanation
The answer is B because the code fragment contains a syntax error that prevents it from compiling. The code fragment tries to catch a StockException in line 10, but the catch block does not have a parameter of type StockException. The catch block should have a parameter of type StockException, such as:
catch (StockException e) { // handle the exception }
This is required by the Java syntax for the catch clause, which must have a parameter that is a subclass of Throwable. Without a parameter, the catch block is invalid and causes a compilation error.
Option A is incorrect because the program does not throw a StockException, as it does not compile.
Option C is incorrect because the program does not throw an OutofStockException, as it does not compile.
Option D is incorrect because the program does not throw a ClassCastException, as it does not compile.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
The try-with-resources Statement (The Java™ Tutorials > Essential Classes > Exceptions) The catch Blocks (The Java™ Tutorials > Essential Classes > Exceptions)
NEW QUESTION # 19
Given the code fragment:
abstract sealed interface SInt permits Story, Art { default String getTitle() { return "Book Title" ; }
}
Which set of class definitions compiles?
- A. Public interface story extends sInd {}
Public interface Art extends SInt {} - B. Non-sealed interface story extends SInt {}
Class Art implements Sint {} - C. Non-sealed interface story extends SInt {}
Non-sealed interaface Art extends Sint {} - D. Sealed interface Storty extends sInt {}
Non-sealed class Art implements Sint {} - E. Interace story extends STnt {}
Interface Art extends SInt {}
Answer: D
Explanation:
Explanation
The answer is C because the code fragment given is an abstract sealed interface SInt that permits Story and Art. The correct answer is option C, which is a sealed interface Story that extends SInt and a non-sealed class Art that implements SInt. This is because a sealed interface can only be extended by the classes or interfaces that it permits, and a non-sealed class can implement a sealed interface.
Option A is incorrect because interface is misspelled as interace, and Story and Art should be capitalized as they are the names of the permitted classes or interfaces.
Option B is incorrect because public is misspelled as public, and sInd should be SInt as it is the name of the sealed interface.
Option D is incorrect because a non-sealed interface cannot extend a sealed interface, as it would violate the restriction of permitted subtypes.
Option E is incorrect because both Story and Art cannot be non-sealed interfaces, as they would also violate the restriction of permitted subtypes.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Sealed Classes and Interfaces in Java 15 | Baeldung
Sealed Class in Java - Javatpoint
NEW QUESTION # 20
Assuming that the data, txt file exists and has the following content:
Text1
Text2
Text3
Given the code fragment:
What is the result?
- A. text1-
text2-
text3-
text3 - B. text1-text2-text3
text3 - C. text1-text2-text3
A java.lang.indexoutofBoundsException is thrown. - D. text1-text2-text3
text1
text2
text3
Answer: B
Explanation:
The answer is D because the code fragment reads the file "data.txt" and collects all the lines in the file into a single string, separated by hyphens. Then, it prints the resulting string. Next, it attempts to read the fourth line in the file (index 3) and print it. However, since the file only has three lines, an IndexOutOfBoundsException is thrown. Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Read contents of a file using Files class in Java
NEW QUESTION # 21
Given the code fragment:
Which code fragment invokes all callable objects in the workers set?
- A.
- B.
- C.
- D.
Answer: C
Explanation:
Explanation
The code fragment in Option C invokes all callable objects in the workers set by using the ExecutorService's invokeAll() method. This method takes a collection of Callable objects and returns a list of Future objects representing the results of the tasks. The other options are incorrect because they either use the wrong method (invokeAny() or submit()) or have syntax errors (missing parentheses or semicolons). References: AbstractExecutorService (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 22
Given the code fragments:
Which action prints Wagon : 200?
- A. At Line n3, replace Car with LuxurayCar.
- B. At line n2, in the main method signature, add throws IoException, ClassNotFoundException.
- C. At line n3, replace readObject (0 with readLine().
- D. At line n2, in the main method signature, add throws IOException, ClassCastException.
- E. At line n1, implement the java.io, Serializable interface.
- F. At Line n1, implement the java.io.AutoCloseable interface
Answer: B
Explanation:
Explanation
The code fragment is trying to read an object from a file using the ObjectInputStream class. This class throws an IOException and a ClassNotFoundException. To handle these exceptions, the main method signature should declare that it throws these exceptions. Otherwise, the code will not compile. If the main method throws these exceptions, the code will print Wagon : 200, which is the result of calling the toString method of the LuxuryCar object that was written to the file. References: ObjectInputStream (Java SE 17 & JDK 17) - Oracle, ObjectOutputStream (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 23
Given:
What is the result?
- A. Compilation fails
- B. 1 Snowy
- C. 0 CLOUDY
- D. 0 Snowy
- E. 1 RAINY
Answer: D
Explanation:
The code is defining an enum class called Forecast with three values: SUNNY, CLOUDY, and RAINY. The toString() method is overridden to always return "SNOWY". In the main method, the ordinal value of SUNNY is printed, which is 0, followed by the value of CLOUDY converted to uppercase, which is "CLOUDY". However, since the toString() method of Forecast returns "SNOWY" regardless of the actual value, the output will be "0 SNOWY". Reference: Enum (Java SE 17 & JDK 17), Enum.EnumDesc (Java SE 17 & JDK 17)
NEW QUESTION # 24
Given:
Which two method invocation execute?
- A. IFace myclassobj = new Myc ();
myclassObj.m3 (); - B. Ifnce.m3 ();
- C. new MyC() .m2 ();
- D. IFace.m2();
- E. iFace mucloassObj = new Myc ();
myClassObj.m4(); - F. IFace .,4():
Answer: C,F
Explanation:
The code given is an interface and a class that implements the interface. The interface has three methods, m1(), m2(), and m3(). The class has one method, m1(). The only two method invocations that will execute are D and E. D is a call to the m2() method in the class, and E is a call to the m3() method in the interface. Reference: https://education.oracle.com/products/trackp_OCPJSE17, 3, 4, 5
NEW QUESTION # 25
Given:
Which statement is true while the program prints GC?
- A. Only the object referenced by t2 is eligible for garbage collection.
- B. Only one of the objects previously referenced by t1 is eligible for garbage collection.
- C. Both the objects previously referenced by t1 are eligible for garbage collection.
- D. None of the objects are eligible for garbage collection.
Answer: C
NEW QUESTION # 26
Given the directory structure:
Given the definition of the Doc class:
Which two are valid definition of the wordDoc class?
- A. Package p1;
Public class wordDoc extends Doc () - B. Package p1, p2;
Public sealed class WordDoc extends Doc () - C. Package p1, p2;
Public non-sealed class WordDoc extends Doc () - D. Package p1;
Public final class WordDoc extends Doc () - E. Package p1,
non-sealed abstract class WordDoc extends Doc () - F. Package p1;
Public non-sealed class wordDoc extends Doc ()
Answer: D,F
Explanation:
The correct answer is A and F because the wordDoc class must be a non-sealed class or a final class to extend the sealed Doc class. Option B is incorrect because the wordDoc class must be non-sealed or final. Option C is incorrect because the wordDoc class cannot be in a different package than the Doc class. Option D is incorrect because the wordDoc class cannot be a sealed class. Option E is incorrect because the wordDoc class cannot be an abstract class. Reference: Oracle Certified Professional: Java SE 17 Developer, 3 Sealed Classes - Oracle Help Center
NEW QUESTION # 27
Given the code fragment:
Which code fragment returns different values?
- A. int sum = listOfNumbers. Stream () reduce ( Integer:: sum) ; +5;
- B. int sum = listOfNumbers. Stream () reduce (0, Integer:: sum) + 5
- C. int sum = listOfNumbers. parallelStream () reduce (5, Integer:: sum) ;
- D. int sum = listOfNumbers. Stream () reduce (5, (a, b) -> a + b) ;
- E. int sum = listOfNumbers. parallelStream () reduce ({m, n) -> m +n) orElse (5) +5;
Answer: A
Explanation:
Explanation
The answer is C because the code fragment uses a different syntax and logic for the reduce operation than the other options. The reduce method in option C takes a single parameter, which is a BinaryOperator that combines two elements of the stream into one. The method returns an Optional, which may or may not contain a value depending on whether the stream is empty or not. The code fragment then adds 5 to the result of the reduce method, regardless of whether it is present or not. This may cause an exception if the Optional is empty, or produce a different value than the other options if the Optional is not empty.
The other options use a different syntax and logic for the reduce operation. They all take two parameters, which are an identity value and a BinaryOperator that combines an element of the stream with an accumulator.
The method returns the final accumulator value, which is equal to the identity value if the stream is empty, or the result of applying the BinaryOperator to all elements of the stream otherwise. The code fragments then add
5 to the result of the reduce method, which will always produce a valid value.
For example, suppose listOfNumbers contains [1, 2, 3]. Then, option A will perform the following steps:
Initialize accumulator to identity value 5
Apply BinaryOperator Integer::sum to accumulator and first element: 5 + 1 = 6 Update accumulator to 6 Apply BinaryOperator Integer::sum to accumulator and second element: 6 + 2 = 8 Update accumulator to 8 Apply BinaryOperator Integer::sum to accumulator and third element: 8 + 3 = 11 Update accumulator to 11 Return final accumulator value 11 Add 5 to final accumulator value: 11 + 5 = 16 Option B will perform the same steps as option A, except using a lambda expression instead of a method reference for the BinaryOperator. Option D will perform the same steps as option A, except using parallelStream instead of stream, which may change the order of applying the BinaryOperator but not the final result. Option E will perform the same steps as option A, except using identity value 0 instead of 5.
Option C, however, will perform the following steps:
Apply BinaryOperator Integer::sum to first and second element: 1 + 2 = 3 Apply BinaryOperator Integer::sum to previous result and third element: 3 + 3 = 6 Return Optional containing final result value 6 Add 5 to Optional value: Optional.of(6) + 5 = Optional.of(11) As you can see, option C produces a different value than the other options, and also uses a different syntax and logic for the reduce operation. References Oracle Certified Professional: Java SE 17 Developer Java SE 17 Developer OCP Oracle Certified Professional Java SE 17 Developer Study Guide Guide to Stream.reduce()
NEW QUESTION # 28
Given:
What is the result?
- A. Software Game Software Game chess 0
- B. Software Game read error
- C. Software game write error
- D. Software Game Software Game Chese 2
- E. Software Game Chess 0
- F. Software Game Chess 2
Answer: D
Explanation:
The answer is B because the code uses the writeObject and readObject methods of the ObjectOutputStream and ObjectInputStream classes to serialize and deserialize the Game object. These methods use the default serialization mechanism, which writes and reads the state of the object's fields, including the inherited ones. Therefore, the title field of the Software class is also serialized and deserialized along with the players field of the Game class. The toString method of the Game class calls the toString method of the Software class using super.toString(), which returns the value of the title field. Hence, when the deserialized object is printed, it shows "Software Game Software Game Chess 2". Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Serialization and Deserialization in Java with Example
NEW QUESTION # 29
Given:
What is the result?
- A. mA
- B. Mb
MC - C. MA
- D. Mb
- E. Mb
Answer: A
Explanation:
Explanation
The code snippet is an example of Java SE 17 code. The code is checking if the object is an instance of class C and if it is, it will print "mC". If it is not an instance of class C, it will print "mA". In this case, the object is not an instance of class C, so the output will be "mA". References: Pattern Matching for instanceof - Oracle Help Center
NEW QUESTION # 30
Given:
Which two modifications enable the code to print Open Close?
- A.
- B.
- C.
- D.
- E.
Answer: B,E
Explanation:
Explanation
The code given is a try-with-resources statement that declares a resource of type AutoCloseable. The resource is an anonymous class that implements the AutoCloseable interface and overrides the close() method. The code also has a print() method that prints the value of the variable s. The code is supposed to print "Open Close", but it does not compile because of two errors.
The first error is at line n1, where the anonymous class is missing a semicolon at the end of its declaration.
This causes a syntax error and prevents the code from compiling. To fix this error, option B adds a semicolon after the closing curly brace of the anonymous class.
The second error is at line n2, where the print() method is called without an object reference. This causes a compilation error because the print() method is not static and cannot be invoked without an object. To fix this error, option E adds an object reference to the print() method by using the variable t.
Therefore, options B and E are correct and enable the code to print "Open Close".
NEW QUESTION # 31
Given:
Which two should the module-info file include for it to represent the service provider interface?
- A. Provides.com.transport.vehicle.cars.Car with com.transport.vehicle.cars. impt, CatImpI;
- B. Exports com.transport.vehicle;
- C. Provides.com.transport.vehicle.cars.Car impl,CarImp1 to com.transport.vehicle.cars. Cars
- D. Requires cm.transport.vehicle,cars:
- E. Requires cm.transport.vehicle,cars:
- F. Exports com.transport.vehicle.cars;
- G. exports com.transport.vehicle.cars.Car;
Answer: A,G
Explanation:
The answer is B and E because the module-info file should include a provides directive and an exports directive to represent the service provider interface. The provides directive declares that the module provides an implementation of a service interface, which is com.transport.vehicle.cars.Car in this case. The with clause specifies the fully qualified name of the service provider class, which is com.transport.vehicle.cars.impl.CarImpl in this case. The exports directive declares that the module exports a package, which is com.transport.vehicle.cars in this case, to make it available to other modules. The package contains the service interface that other modules can use.
Option A is incorrect because requires is not the correct keyword to declare a service provider interface. Requires declares that the module depends on another module, which is not the case here.
Option C is incorrect because it has a typo in the module name. It should be com.transport.vehicle.cars, not cm.transport.vehicle.cars.
Option D is incorrect because it has a typo in the keyword provides. It should be provides, not Provides. It also has a typo in the service interface name. It should be com.transport.vehicle.cars.Car, not com.transport.vehicle.cars.Car impl. It also has an unnecessary to clause, which is used to limit the accessibility of an exported package to specific modules.
Option F is incorrect because it exports the wrong package. It should export com.transport.vehicle.cars, not com.transport.vehicle.cars.impl. The impl package contains the service provider class, which should not be exposed to other modules.
Option G is incorrect because it exports the wrong package. It should export com.transport.vehicle.cars, not com.transport.vehicle. The vehicle package does not contain the service interface or the service provider class. Reference:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Java Modules - Service Interface Module - GeeksforGeeks
Java Service Provider Interface | Baeldung
NEW QUESTION # 32
Given the code fragment:
What is the result:
- A. ADEABCB // the order of element is unpredictable
- B. ABCDE // the order of elements is unpredictable
- C. ABBCDE // the order of elements is unpredictable
- D. ABCE
Answer: C
Explanation:
Explanation
The answer is D because the code fragment uses the Stream API to create two streams, s1 and s2, and then concatenates them using the concat() method. The resulting stream is then processed in parallel using the parallel() method, and the distinct() method is used to remove duplicate elements. Finally, the forEach() method is used to print the elements of the resulting stream to the console. Since the order of elements in a parallel stream is unpredictable, the output could be any of the options given, but option D is the most likely.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Parallelizing Streams
NEW QUESTION # 33
Which statement is true about migration?
- A. Unnamed modules are automatic modules in a top-down migration.
- B. Every module is moved to the module path in a top-down migration.
- C. The required modules migrate before the modules that depend on them in a top-down ^migration.
- D. Every module is moved to the module path in a bottom-up migration.
Answer: D
Explanation:
Explanation
The answer is B because a bottom-up migration is a strategy for modularizing an existing application by moving its dependencies to the module path one by one, starting from the lowest-level libraries and ending with the application itself. This way, each module can declare its dependencies on other modules using the module-info.java file, and benefit from the features of the Java Platform Module System (JPMS), such as reliable configuration, strong encapsulation, and service loading.
Option A is incorrect because a top-down migration is a strategy for modularizing an existing application by moving it to the module path first, along with its dependencies as automatic modules. Automatic modules are non-modular JAR files that are treated as modules with some limitations, such as not having a module descriptor or a fixed name. A top-down migration allows the application to use the module path without requiring all of its dependencies to be modularized first.
Option C is incorrect because a top-down migration does not require any specific order of migrating modules, as long as the application is moved first and its dependencies are moved as automatic modules. A bottom-up migration, on the other hand, requires the required modules to migrate before the modules that depend on them.
Option D is incorrect because unnamed modules are not automatic modules in any migration strategy.
Unnamed modules are modules that do not have a name or a module descriptor, such as classes loaded from the class path or dynamically generated classes. Unnamed modules have unrestricted access to all other modules, but they cannot be accessed by named modules, except through reflection with reduced security checks. References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Migrating to Modules (How and When) - JavaDeploy
Java 9 Modularity: Patterns and Practices for Developing Maintainable Applications
NEW QUESTION # 34
Given:
What is the result?
- A. 0
- B. 1
- C. 2
- D. Nothing is printed because of an indefinite loop.
- E. 3
- F. Compilation fails.
- G. A runtime exception is thrown.
- H. 4
Answer: F
Explanation:
Explanation
The code will not compile because the variable 'x' is declared as final and then it is being modified in the switch statement. This is not allowed in Java. A final variable is a variable whose value cannot be changed once it is initialized1. The switch statement tries to assign different values to 'x' depending on the value of 'y', which violates the final modifier. The compiler will report an error: The final local variable x cannot be assigned. It must be blank and not using a compound assignment. References: The final Keyword (The Java™ Tutorials > Learning the Java Language > Classes and Objects)
NEW QUESTION # 35
Given:
What is the result?
- A. Wtablechair tableChair
- B. wTableChair TableChair
- C. A RuntimeException is thrown
- D. Tablechair Tablechair
- E. Compilation fails
Answer: E
Explanation:
The code fragment will fail to compile because the class name and the constructor name do not match. The class name is Furniture, but the constructor name is Wtable. This will cause a syntax error. The correct way to define a constructor is to use the same name as the class name. Therefore, the code fragment should change the constructor name to Furniture or change the class name to Wtable.
NEW QUESTION # 36
Given the code fragment:
What is the result?
- A. Range 1
Range 2
Range 3
Range 1
Not a valida rank - B. Range1
Note a valid rank. - C. Range 1
Range 2
Range 3 - D. Range 1
Answer: A
Explanation:
Explanation
The code fragment is using the switch statement with the new Java 17 syntax. The switch statement checks the value of the variable rank and executes the corresponding case statement. In this case, the value of rank is 4, so the first case statement is executed, printing "Range1". The second and third case statements are also executed, printing "Range2" and "Range3". The default case statement is also executed, printing "Not a valid rank". References: Java Language Changes - Oracle Help Center
NEW QUESTION # 37
......
To pass the Oracle 1Z0-829 certification exam, candidates need to demonstrate their proficiency in developing applications using Java SE 17 technologies. 1z1-829 exam consists of multiple-choice questions and requires candidates to complete the exam within a specific time frame. 1z1-829 exam covers a wide range of topics, including Java language features, data types, control structures, and object-oriented programming concepts.
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